What is (\partial)/(\partial x)(x^2*y^2) ?

The answer to (\partial)/(\partial x)(x^2*y^2) is 2xy^2

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(\partial)/(\partial x)(x^2*y^2)

\frac{\partial}{\partial x} (x^{2} \cdot y^{2})

2 x y^{2}

Solution steps

\frac{\partial}{\partial x} (x^{2} y^{2})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= y^{2} \frac{\partial}{\partial x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= y^{2} \cdot 2 x^{2 - 1}

Simplify

= 2 x y^{2}

\frac{0.5}{s + 1}

\int \frac{ln ( 2 x )}{x} d x

\int 5 sin^{4} (x) cos (x) d x

\int x^{3} 196 - x^{2} d x

\frac{d}{d x} (a^{x} ln (a))

What is (\partial)/(\partial x)(x^2*y^2) ?
The answer to (\partial)/(\partial x)(x^2*y^2) is 2xy^2