What is the tangent of 4x^2+y^2=25,(2,3) ?

The tangent of 4x^2+y^2=25,(2,3) is y=-8/3 x+25/3

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tangent of 4x^2+y^2=25,(2,3)

tangent of

4 x^{2} + y^{2} = 25, (2, 3)

y = - \frac{8}{3} x + \frac{25}{3}

Solution steps

Find the slope of

4 x^{2} + y^{2} = 25 : \frac{d y}{d x} = - \frac{4 x}{y}

Compute the slope of

4 x^{2} + y^{2} = 25

(2, 3) : m = - \frac{8}{3}

Find the line with slope m=

- \frac{8}{3}

and passing through

(2, 3) : y = - \frac{8}{3} x + \frac{25}{3}

y = - \frac{8}{3} x + \frac{25}{3}

70 x^{- 5}

\int \frac{x ^{2}}{( a + b x ^{3} ) ^{2}} d x

x \to 0 + lim ((tan (7 x))^{x})

(2 y^{2} + 3 x) d x + 4 x y d y = 0

\int \frac{x ^{3} - 3 x + 4}{x} d x

What is the tangent of 4x^2+y^2=25,(2,3) ?
The tangent of 4x^2+y^2=25,(2,3) is y=-8/3 x+25/3