What is the derivative of y=sqrt(x^2+8) ?

The derivative of y=sqrt(x^2+8) is x/(sqrt(x^2+8))

What is the first derivative of y=sqrt(x^2+8) ?

The first derivative of y=sqrt(x^2+8) is x/(sqrt(x^2+8))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

y = x^{2} + 8

\frac{x}{x ^{2} + 8}

Solution steps

\frac{d}{d x} (x^{2} + 8)

Apply the chain rule:

\frac{1}{2 x ^{2} + 8} \frac{d}{d x} (x^{2} + 8)

= \frac{1}{2 x ^{2} + 8} \frac{d}{d x} (x^{2} + 8)

\frac{d}{d x} (x^{2} + 8) = 2 x

= \frac{1}{2 x ^{2} + 8} \cdot 2 x

Simplify

\frac{1}{2 x ^{2} + 8} \cdot 2 x : \frac{x}{x ^{2} + 8}

= \frac{x}{x ^{2} + 8}

x \to 0 + lim (cot (3 x))

\frac{\partial}{\partial y} (3 x y^{2})

\frac{d}{d x} (\frac{tan ( 3 x )}{x ^{2}})

\frac{\partial}{\partial y} (5 y)

What is the derivative of y=sqrt(x^2+8) ?
The derivative of y=sqrt(x^2+8) is x/(sqrt(x^2+8))
What is the first derivative of y=sqrt(x^2+8) ?
The first derivative of y=sqrt(x^2+8) is x/(sqrt(x^2+8))