What is (\partial)/(\partial x)(2x^2-3y-4) ?

The answer to (\partial)/(\partial x)(2x^2-3y-4) is 4x

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(\partial)/(\partial x)(2x^2-3y-4)

\frac{\partial}{\partial x} (2 x^{2} - 3 y - 4)

4 x

Solution steps

\frac{\partial}{\partial x} (2 x^{2} - 3 y - 4)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 x^{2}) - \frac{\partial}{\partial x} (3 y) - \frac{\partial}{\partial x} (4)

\frac{\partial}{\partial x} (2 x^{2}) = 4 x

\frac{\partial}{\partial x} (3 y) = 0

\frac{\partial}{\partial x} (4) = 0

= 4 x - 0 - 0

Simplify

= 4 x

\frac{d}{d x} (e^{2 x} - 3)

(9 x^{2} - 15 x) e^{x}

4 e^{x^{2}}

\frac{d}{d x} (\frac{2 x}{2 x ^{2} + 1})

f (x) = 4 - x - \frac{2}{3}

What is (\partial)/(\partial x)(2x^2-3y-4) ?
The answer to (\partial)/(\partial x)(2x^2-3y-4) is 4x