What is the slope ofintercept (1/2 ,-1/2),(5,-1/2) ?

The slope ofintercept (1/2 ,-1/2),(5,-1/2) is y=(-1/2)

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slope ofintercept (1/2 ,-1/2),(5,-1/2)

slope intercept

(\frac{1}{2}, - \frac{1}{2}), (5, - \frac{1}{2})

y = (- \frac{1}{2})

Solution steps

Compute the slope

(\frac{1}{2}, - \frac{1}{2}), (5, - \frac{1}{2}) : m = 0

Compute the

y

intercept:

b = - \frac{1}{2}

Construct the line equation

y = mx + b

where

m = 0

and

b = - \frac{1}{2}

y = (- \frac{1}{2})

\int (12 x^{2} - 6 x + 2) d x

\frac{\partial}{\partial y} (sin (x y) + x y cos (x y))

\frac{\partial}{\partial x} (x (x^{2} - 3 y^{2}))

x \to 0 lim (\frac{e ^{2 x - 1}}{tan ( x )})

4 e^{2 t}

What is the slope ofintercept (1/2 ,-1/2),(5,-1/2) ?
The slope ofintercept (1/2 ,-1/2),(5,-1/2) is y=(-1/2)