What is the derivative of y=2tan^2(2x)-1 ?

The derivative of y=2tan^2(2x)-1 is 8sec^2(2x)tan(2x)

What is the first derivative of y=2tan^2(2x)-1 ?

The first derivative of y=2tan^2(2x)-1 is 8sec^2(2x)tan(2x)

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derivative of

y = 2 tan^{2} (2 x) - 1

8 sec^{2} (2 x) tan (2 x)

Solution steps

\frac{d}{d x} (2 tan^{2} (2 x) - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 tan^{2} (2 x)) - \frac{d}{d x} (1)

\frac{d}{d x} (2 tan^{2} (2 x)) = 8 sec^{2} (2 x) tan (2 x)

\frac{d}{d x} (1) = 0

= 8 sec^{2} (2 x) tan (2 x) - 0

Simplify

= 8 sec^{2} (2 x) tan (2 x)

\frac{4 - x e ^{x}}{x + e ^{x}}

\frac{d y}{d t} = \frac{1}{t} y + 3 t

\frac{50}{100 s + 0.01 s ^{2}}

\int \frac{4}{16 - x ^{2}} d x

t^{2} y^{^{''}} + 19 t y^{^{'}} + 82 y = 0

What is the derivative of y=2tan^2(2x)-1 ?
The derivative of y=2tan^2(2x)-1 is 8sec^2(2x)tan(2x)
What is the first derivative of y=2tan^2(2x)-1 ?
The first derivative of y=2tan^2(2x)-1 is 8sec^2(2x)tan(2x)