What is (\partial)/(\partial t)(rcos(t)) ?

The answer to (\partial)/(\partial t)(rcos(t)) is -rsin(t)

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(\partial)/(\partial t)(rcos(t))

\frac{\partial}{\partial t} (r cos (t))

- r sin (t)

Solution steps

\frac{\partial}{\partial t} (r cos (t))

Treat

r

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= r \frac{\partial}{\partial t} (cos (t))

Apply the common derivative:

\frac{\partial}{\partial t} (cos (t)) = - sin (t)

= r (- sin (t))

Simplify

= - r sin (t)

\frac{4 e ^{4 x}}{e ^{8} ( e ^{16} - 1 )}

\int \frac{2 x}{25 - x ^{2}} d x

e^{- \frac{t}{2}}

\int \frac{8}{x ^{2} + 16} d x

\int \frac{3 + 8 x - 2 x ^{3}}{4 x} d x

What is (\partial)/(\partial t)(rcos(t)) ?
The answer to (\partial)/(\partial t)(rcos(t)) is -rsin(t)