What is the integral from 0 to pi/2 of cos(θ) ?

The integral from 0 to pi/2 of cos(θ) is 1

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integral from 0 to pi/2 of cos(θ)

\int_{0}^{\frac{π}{2}} cos (θ) d θ

1

Solution steps

\int_{0}^{\frac{π}{2}} cos (θ) d θ

Use the common integral:

\int cos (θ) d θ = sin (θ)

= [sin (θ)]_{0}^{\frac{π}{2}}

Compute the boundaries:

1

= 1

\frac{\partial}{\partial x} (x y^{- 1})

\int \frac{1}{6 y ^{2}} d y

\int_{a}^{b} x (b - x)^{2} d x

f (- 4) = 3 x + \frac{2}{x}

\int_{4}^{16} \frac{1}{7 - x} d x

What is the integral from 0 to pi/2 of cos(θ) ?
The integral from 0 to pi/2 of cos(θ) is 1