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Popular >

(y^2-xy)dx+(x^2)dy=0

Solution

(y^{2} - x y) d x + (x^{2}) d y = 0

Solution

y = \frac{x}{ln ( x ) + c _{1}}

Solution steps

(y^{2} - x y) d x + (x^{2}) d y = 0

Solve Bernoulli ODE:

y = \frac{x}{ln ( x ) + c _{1}}

y = \frac{x}{ln ( x ) + c _{1}}

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Frequently Asked Questions (FAQ)

What is the solution for (y^2-xy)dx+(x^2)dy=0 ?
The solution for (y^2-xy)dx+(x^2)dy=0 is y= x/(ln(x)+c_{1)}