What is the solution for (2x+3)y^'=y+sqrt(2x+3) ?

The solution for (2x+3)y^'=y+sqrt(2x+3) is y= 1/2 ln(2x+3)sqrt(2x+3)+c_{1}sqrt(2x+3)

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(2x+3)y^'=y+sqrt(2x+3)

(2 x + 3) y^{^{'}} = y + 2 x + 3

y = \frac{1}{2} ln (2 x + 3) 2 x + 3 + c_{1} 2 x + 3

Solution steps

(2 x + 3) y^{'} (x) = y + 2 x + 3

Solve linear ODE:

y = \frac{1}{2} ln (2 x + 3) 2 x + 3 + c_{1} 2 x + 3

y = \frac{1}{2} ln (2 x + 3) 2 x + 3 + c_{1} 2 x + 3

\frac{1 d y}{x ^{2} d x} = y^{2} + 9

2^{90}

f (x) = 2 x^{2} - 7 x + 5

\frac{d}{d x} (\frac{e ^{4 x^{2} + 1}}{8})

\frac{d}{d x} (- 2 x sin (2 x))

What is the solution for (2x+3)y^'=y+sqrt(2x+3) ?
The solution for (2x+3)y^'=y+sqrt(2x+3) is y= 1/2 ln(2x+3)sqrt(2x+3)+c_{1}sqrt(2x+3)