What is the solution for 7x^2y+y^'=6x^2 ?

The solution for 7x^2y+y^'=6x^2 is y=(e^{(-7x^3+c_{1})/3})/(7)+6/7

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7x^2y+y^'=6x^2

7 x^{2} y + y^{^{'}} = 6 x^{2}

y = \frac{e ^{\frac{- 7 x ^{3} + c _{1}}{3}}}{7} + \frac{6}{7}

Solution steps

7 x^{2} y + y^{'} (x) = 6 x^{2}

Solve separable ODE:

y = \frac{e ^{\frac{- 7 x ^{3} + c _{1}}{3}}}{7} + \frac{6}{7}

y = \frac{e ^{\frac{- 7 x ^{3} + c _{1}}{3}}}{7} + \frac{6}{7}

y^{^{'''}} - 5 y^{^{''}} - 6 y^{^{'}} = 0

\frac{d}{d t} (t)

x y^{^{'}} - 4 y = x

f (t) = cos (t)

x \to 0 lim ((1 + 7 x)^{\frac{2}{x}})

What is the solution for 7x^2y+y^'=6x^2 ?
The solution for 7x^2y+y^'=6x^2 is y=(e^{(-7x^3+c_{1})/3})/(7)+6/7