What is the solution for (d^2x)/(dt^2)=5+2x ?

The solution for (d^2x)/(dt^2)=5+2x is x=c_{1}e^{sqrt(2)t}+c_{2}e^{-sqrt(2)t}-5/2

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(d^2x)/(dt^2)=5+2x

\frac{d ^{2} x}{d t ^{2}} = 5 + 2 x

x = c_{1} e^{2 t} + c_{2} e^{- 2 t} - \frac{5}{2}

Solution steps

\frac{d ^{2} x}{d t ^{2}} = 5 + 2 x

Solve linear ODE:

x = c_{1} e^{2 t} + c_{2} e^{- 2 t} - \frac{5}{2}

x = c_{1} e^{2 t} + c_{2} e^{- 2 t} - \frac{5}{2}

\frac{d N}{d t} + N = Nt e^{t + 3}

5 x + 6

x + y

\int \frac{1 - x}{1 + x} d x

\frac{1}{2 x} + \frac{1}{3 x ^{\frac{2}{3}}}

What is the solution for (d^2x)/(dt^2)=5+2x ?
The solution for (d^2x)/(dt^2)=5+2x is x=c_{1}e^{sqrt(2)t}+c_{2}e^{-sqrt(2)t}-5/2