What is laplacetransform 3cos(4t) ?

The answer to laplacetransform 3cos(4t) is (3s)/(s^2+16)

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laplacetransform 3cos(4t)

laplace transform

3 cos (4 t)

\frac{3 s}{s ^{2} + 16}

Solution steps

L {3 cos (4 t)}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= 3 L {cos (4 t)}

L {cos (4 t)} : \frac{s}{s ^{2} + 16}

= 3 \cdot \frac{s}{s ^{2} + 16}

Refine

3 \frac{s}{s ^{2} + 16} : \frac{3 s}{s ^{2} + 16}

= \frac{3 s}{s ^{2} + 16}

\int e^{\frac{2}{x}} d x

\int 10 x + 3 x^{2} + 12 x^{3} + C d x

\frac{( s + 1 )}{s ^{2} + 2 s + 2}

h \to 0 lim (h - \frac{9}{h} + 4)

\int \frac{x ^{2} - 5 x + 2}{3 x} d x

What is laplacetransform 3cos(4t) ?
The answer to laplacetransform 3cos(4t) is (3s)/(s^2+16)