What is the tangent of y=sqrt(10x),(10,10) ?

The tangent of y=sqrt(10x),(10,10) is y= 1/2 x+5

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tangent of y=sqrt(10x),(10,10)

tangent of

y = 10 x, (10, 10)

y = \frac{1}{2} x + 5

Solution steps

Find the slope of

y = 10 x : \frac{d y}{d x} = \frac{5}{2 x}

Compute the slope of

y = 10 x

(10, 10) : m = \frac{1}{2}

Find the line with slope m=

\frac{1}{2}

and passing through

(10, 10) : y = \frac{1}{2} x + 5

y = \frac{1}{2} x + 5

\frac{d}{d x} (ln (5 - x^{2}))

\int_{2}^{4} \frac{1}{16 - t ^{2}} d t

x \to 2 lim (2 x - 2)

\int \frac{x ^{3}}{x ^{2} - 2 x + 4} d x

\int \frac{sec ( x )}{x} d x

What is the tangent of y=sqrt(10x),(10,10) ?
The tangent of y=sqrt(10x),(10,10) is y= 1/2 x+5