What is (\partial)/(\partial x)(cos(6y-2x)) ?

The answer to (\partial)/(\partial x)(cos(6y-2x)) is 2sin(6y-2x)

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(\partial)/(\partial x)(cos(6y-2x))

\frac{\partial}{\partial x} (cos (6 y - 2 x))

2 sin (6 y - 2 x)

Solution steps

\frac{\partial}{\partial x} (cos (6 y - 2 x))

Treat

y

as a constant

Apply the chain rule:

- sin (6 y - 2 x) \frac{\partial}{\partial x} (6 y - 2 x)

= - sin (6 y - 2 x) \frac{\partial}{\partial x} (6 y - 2 x)

\frac{\partial}{\partial x} (6 y - 2 x) = - 2

= - sin (6 y - 2 x) (- 2)

Simplify

= 2 sin (6 y - 2 x)

\frac{\partial}{\partial x} (y^{6} cos (6 x) \cdot 6)

y = \frac{1}{( 7 x + 16 ) ^{4}}

7 sec (x)

\frac{\partial}{\partial x} (\frac{y}{y - 4 x})

\frac{( e ^{x} )}{1 + x}

What is (\partial)/(\partial x)(cos(6y-2x)) ?
The answer to (\partial)/(\partial x)(cos(6y-2x)) is 2sin(6y-2x)