What is maclaurin ((5x-2))/((x+1)),4 ?

The answer to maclaurin ((5x-2))/((x+1)),4 is -2+7x-7x^2+7x^3-7x^4+\ldots

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maclaurin ((5x-2))/((x+1)),4

maclaurin

\frac{( 5 x - 2 )}{( x + 1 )}, 4

- 2 + 7 x - 7 x^{2} + 7 x^{3} - 7 x^{4} + \dots

Solution steps

Apply the Maclaurin Formula

= - 2 + \frac{\frac{d}{d x} ( \frac{5 x - 2}{x + 1} ) ( 0 )}{1 !} x + \frac{\frac{d ^{2}}{d x ^{2}} ( \frac{5 x - 2}{x + 1} ) ( 0 )}{2 !} x^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( \frac{5 x - 2}{x + 1} ) ( 0 )}{3 !} x^{3} + \dots

Evaluate Derivatives

= - 2 + \frac{7}{1 !} x + \frac{- 14}{2 !} x^{2} + \frac{42}{3 !} x^{3} + \frac{- 168}{4 !} x^{4} + \dots

Refine

= - 2 + 7 x - 7 x^{2} + 7 x^{3} - 7 x^{4} + \dots

\frac{d}{d x} ((2 x^{3} - 3) (sin (x) + 2))

3 cos (x), 3 cos (2 x), 0 \leq x \leq π

(1 + y^{2} sin (2 x)) d x - 2 y cos^{2} (x) d y = 0

\frac{d y}{d x} = x y^{3}

\int \frac{1}{x ^{2} + 12} d x

What is maclaurin ((5x-2))/((x+1)),4 ?
The answer to maclaurin ((5x-2))/((x+1)),4 is -2+7x-7x^2+7x^3-7x^4+\ldots