What is the limit as x approaches pi/2 of cos(x) ?

The limit as x approaches pi/2 of cos(x) is 0

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limit as x approaches pi/2 of cos(x)

x \to \frac{π}{2} lim (cos (x))

0

Solution steps

x \to \frac{π}{2} lim (cos (x))

Plug in the value

x = \frac{π}{2}

= cos (\frac{π}{2})

Use the following trivial identity:

cos (\frac{π}{2}) = 0

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= 0

\int \frac{1}{x x ^{2} - 64} d x

\int \frac{x ^{2}}{12} d x

f (x) = 8 6 x^{2} + 7

\int (\frac{x + 2}{x ^{2} + 4 x}) d x

What is the limit as x approaches pi/2 of cos(x) ?
The limit as x approaches pi/2 of cos(x) is 0