What is (\partial)/(\partial y)(xycos(z)) ?

The answer to (\partial)/(\partial y)(xycos(z)) is xcos(z)

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(\partial)/(\partial y)(xycos(z))

\frac{\partial}{\partial y} (x y cos (z))

x cos (z)

Solution steps

\frac{\partial}{\partial y} (x y cos (z))

Treat

x, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x cos (z) \frac{\partial}{\partial y} (y)

Apply the common derivative:

\frac{\partial}{\partial y} (y) = 1

= x cos (z) \cdot 1

Simplify

= x cos (z)

\int sin (x y) d x

\int_{- 1}^{x} 1.5 x^{2} d x

f (x) = \frac{x ^{5} + 4 x}{x ^{3}}

y^{^{'}} = (1 - y) \cdot sin (x)

\int_{2}^{3} \frac{18}{3 - x} d x

What is (\partial)/(\partial y)(xycos(z)) ?
The answer to (\partial)/(\partial y)(xycos(z)) is xcos(z)