What is the tangent of 3x-32sqrt(x),\at x=4 ?

The tangent of 3x-32sqrt(x),\at x=4 is y=-5x-32

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of 3x-32sqrt(x),\at x=4

tangent of

3 x - 32 x, at x = 4

y = - 5 x - 32

Solution steps

Find the tangent point:

(4, - 52)

Find the slope of

y = 3 x - 32 x : \frac{d y}{d x} = 3 - \frac{16}{x}

Compute the slope of

y = 3 x - 32 x

x = 4 : m = - 5

Find the line with slope m=

- 5

and passing through

(4, - 52) : y = - 5 x - 32

y = - 5 x - 32

y = x^{2} - 12, y = x - 6

\frac{\partial}{\partial x} (x + \frac{x - y}{y - z})

\frac{d}{d x} (tan (cos (\frac{x}{2})))

\int e^{x^{3} + 5} \cdot x^{2} d x

\int \frac{8 - e ^{x}}{e ^{5 x}} d x

What is the tangent of 3x-32sqrt(x),\at x=4 ?
The tangent of 3x-32sqrt(x),\at x=4 is y=-5x-32