What is (\partial)/(\partial x)(cos(2x+2y)) ?

The answer to (\partial)/(\partial x)(cos(2x+2y)) is -sin(2x+2y)*2

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(\partial)/(\partial x)(cos(2x+2y))

\frac{\partial}{\partial x} (cos (2 x + 2 y))

- sin (2 x + 2 y) \cdot 2

Solution steps

\frac{\partial}{\partial x} (cos (2 x + 2 y))

Treat

y

as a constant

Apply the chain rule:

- sin (2 x + 2 y) \frac{\partial}{\partial x} (2 x + 2 y)

= - sin (2 x + 2 y) \frac{\partial}{\partial x} (2 x + 2 y)

\frac{\partial}{\partial x} (2 x + 2 y) = 2

= - sin (2 x + 2 y) \cdot 2

n = 1 \sum \infty - \frac{3}{2 ^{n}}

\int \frac{x ^{2}}{13 - 4 x + x ^{2}} d x

\frac{- 3 x - 16 x}{2 x ^{\frac{1}{3}}}

y^{^{''}} + 20 y^{^{'}} + 200 y = 0

y^{^{''}} + 8 y^{^{'}} + 13 y = 0

What is (\partial)/(\partial x)(cos(2x+2y)) ?
The answer to (\partial)/(\partial x)(cos(2x+2y)) is -sin(2x+2y)*2