What is the derivative of 7e^{7e^x+x} ?

The derivative of 7e^{7e^x+x} is 7e^{7e^x+x}(7e^x+1)

What is the first derivative of 7e^{7e^x+x} ?

The first derivative of 7e^{7e^x+x} is 7e^{7e^x+x}(7e^x+1)

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derivative of

7 e^{7 e^{x} + x}

7 e^{7 e^{x} + x} (7 e^{x} + 1)

Solution steps

\frac{d}{d x} (7 e^{7 e^{x} + x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 7 \frac{d}{d x} (e^{7 e^{x} + x})

Apply the chain rule:

e^{7 e^{x} + x} \frac{d}{d x} (7 e^{x} + x)

= e^{7 e^{x} + x} \frac{d}{d x} (7 e^{x} + x)

\frac{d}{d x} (7 e^{x} + x) = 7 e^{x} + 1

= 7 e^{7 e^{x} + x} (7 e^{x} + 1)

f (z) = 3 x + 2 z + 4 x z

f (x) = 12 x^{4} + 3 x^{3} + 5 x^{- 2} - 4

\int sin^{2} (b x) cos (b x) d x

\int 3 x - 2 d x

\frac{d}{d x} (\frac{5}{x + 2})

What is the derivative of 7e^{7e^x+x} ?
The derivative of 7e^{7e^x+x} is 7e^{7e^x+x}(7e^x+1)
What is the first derivative of 7e^{7e^x+x} ?
The first derivative of 7e^{7e^x+x} is 7e^{7e^x+x}(7e^x+1)