What is the integral from-infinity to 0 of 1/(3-4x) ?

The integral from-infinity to 0 of 1/(3-4x) is diverges

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integral from-infinity to 0 of 1/(3-4x)

\int_{- \infty}^{0} \frac{1}{3 - 4 x} d x

diverges

Solution steps

\int_{- \infty}^{0} \frac{1}{3 - 4 x} d x

Compute the indefinite integral:

\int \frac{1}{3 - 4 x} d x = - \frac{1}{4} ln ∣ 3 - 4 x ∣ + C

Compute the boundaries:

\int_{- \infty}^{0} \frac{1}{3 - 4 x} d x =

diverges

= diverges

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- x^{2} - x + 9, - 0.75 x + 6, x = 0

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What is the integral from-infinity to 0 of 1/(3-4x) ?
The integral from-infinity to 0 of 1/(3-4x) is diverges