What is the derivative of g(x)=x^2+3x^3 ?

The derivative of g(x)=x^2+3x^3 is 2x+9x^2

What is the first derivative of g(x)=x^2+3x^3 ?

The first derivative of g(x)=x^2+3x^3 is 2x+9x^2

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derivative of

g (x) = x^{2} + 3 x^{3}

2 x + 9 x^{2}

Solution steps

\frac{d}{d x} (x^{2} + 3 x^{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (3 x^{3})

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (3 x^{3}) = 9 x^{2}

= 2 x + 9 x^{2}

\frac{d y}{d x} (x y) = 7

f (x) = \frac{x ^{2} - 7}{16 - x ^{2}}

\int lo g_{a} (x) d x

\frac{\partial}{\partial y} (x y^{\frac{1}{2}})

\frac{d}{d x} ((3 - x^{2}) (x^{3} - 5 x + 2))

What is the derivative of g(x)=x^2+3x^3 ?
The derivative of g(x)=x^2+3x^3 is 2x+9x^2
What is the first derivative of g(x)=x^2+3x^3 ?
The first derivative of g(x)=x^2+3x^3 is 2x+9x^2