What is the derivative of ((x^2-5x)/(x+1)) ?

The derivative of ((x^2-5x)/(x+1)) is (x^2+2x-5)/((x+1)^2)

What is the first derivative of ((x^2-5x)/(x+1)) ?

The first derivative of ((x^2-5x)/(x+1)) is (x^2+2x-5)/((x+1)^2)

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\frac{d}{d x} (\frac{( x ^{2} - 5 x )}{x + 1})

\frac{x ^{2} + 2 x - 5}{( x + 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{( x ^{2} - 5 x )}{x + 1})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{2} - 5 x ) ( x + 1 ) - \frac{d}{d x} ( x + 1 ) ( x ^{2} - 5 x )}{( x + 1 ) ^{2}}

\frac{d}{d x} (x^{2} - 5 x) = 2 x - 5

\frac{d}{d x} (x + 1) = 1

= \frac{( 2 x - 5 ) ( x + 1 ) - 1 \cdot ( x ^{2} - 5 x )}{( x + 1 ) ^{2}}

Simplify

\frac{( 2 x - 5 ) ( x + 1 ) - 1 \cdot ( x ^{2} - 5 x )}{( x + 1 ) ^{2}} : \frac{x ^{2} + 2 x - 5}{( x + 1 ) ^{2}}

= \frac{x ^{2} + 2 x - 5}{( x + 1 ) ^{2}}

\int \frac{x + 5}{5 - x} d x

\frac{d}{d x} ((5 x^{3} - 8)^{10})

x \to 6 - lim (5)

y^{^{''}} + y^{^{'}} - 2 y = 2 t, y (0) = 0, y^{^{'}} (0) = 1

y^{^{'}} = \frac{y ^{2} - y}{x}, y (1) = - 2

What is the derivative of ((x^2-5x)/(x+1)) ?
The derivative of ((x^2-5x)/(x+1)) is (x^2+2x-5)/((x+1)^2)
What is the first derivative of ((x^2-5x)/(x+1)) ?
The first derivative of ((x^2-5x)/(x+1)) is (x^2+2x-5)/((x+1)^2)