What is the solution for ((x^2+1)dy)/(dx)+9x(y-1)=0 ?

The solution for ((x^2+1)dy)/(dx)+9x(y-1)=0 is y=(c_{1})/((x^2+1)^{9/2)}+1

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((x^2+1)dy)/(dx)+9x(y-1)=0

\frac{( x ^{2} + 1 ) d y}{d x} + 9 x (y - 1) = 0

y = \frac{c _{1}}{( x ^{2} + 1 ) ^{\frac{9}{2}}} + 1

Solution steps

\frac{( x ^{2} + 1 ) d y}{d x} + 9 x (y - 1) = 0

Solve separable ODE:

y = \frac{c _{1}}{( x ^{2} + 1 ) ^{\frac{9}{2}}} + 1

y = \frac{c _{1}}{( x ^{2} + 1 ) ^{\frac{9}{2}}} + 1

\frac{d}{d x} (tan^{2} (x) - 1)

\int \frac{6}{x ^{2} x ^{2} - 9} d x

\frac{d}{d x} (5^{x - 2})

f (x) = 2 x^{3} + 9 x^{2} - 60 x + 4

\frac{d}{d x} (\frac{( 2 x ^{2} + 8 x + 6 )}{x})

What is the solution for ((x^2+1)dy)/(dx)+9x(y-1)=0 ?
The solution for ((x^2+1)dy)/(dx)+9x(y-1)=0 is y=(c_{1})/((x^2+1)^{9/2)}+1