What is the derivative of f(x)=arcsin(4x) ?

The derivative of f(x)=arcsin(4x) is 4/(sqrt(1-16x^2))

What is the first derivative of f(x)=arcsin(4x) ?

The first derivative of f(x)=arcsin(4x) is 4/(sqrt(1-16x^2))

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derivative of

f (x) = arcsin (4 x)

\frac{4}{1 - 16 x ^{2}}

Solution steps

\frac{d}{d x} (arcsin (4 x))

Apply the chain rule:

\frac{1}{1 - ( 4 x ) ^{2}} \frac{d}{d x} (4 x)

= \frac{1}{1 - ( 4 x ) ^{2}} \frac{d}{d x} (4 x)

\frac{d}{d x} (4 x) = 4

= \frac{1}{1 - ( 4 x ) ^{2}} \cdot 4

Simplify

\frac{1}{1 - ( 4 x ) ^{2}} \cdot 4 : \frac{4}{1 - 16 x ^{2}}

= \frac{4}{1 - 16 x ^{2}}

f (x) = - 6 x^{2} - 10 x, at x = 1

\frac{t ^{2} + 1}{t ^{2} - 1}

y = x (2 x + 3)^{5}

\frac{\partial}{\partial x} (arcsin (x - y))

\int (x^{n}) d x

What is the derivative of f(x)=arcsin(4x) ?
The derivative of f(x)=arcsin(4x) is 4/(sqrt(1-16x^2))
What is the first derivative of f(x)=arcsin(4x) ?
The first derivative of f(x)=arcsin(4x) is 4/(sqrt(1-16x^2))