What is the derivative of y=b^2(a-x)3 ?

The derivative of y=b^2(a-x)3 is -3b^2

What is the first derivative of y=b^2(a-x)3 ?

The first derivative of y=b^2(a-x)3 is -3b^2

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derivative of

y = b^{2} (a - x) 3

- 3 b^{2}

Solution steps

\frac{d}{d x} (b^{2} (a - x) \cdot 3)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= b^{2} \cdot 3 \frac{d}{d x} (a - x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= b^{2} \cdot 3 (\frac{d a}{d x} - \frac{d x}{d x})

\frac{d a}{d x} = 0

\frac{d x}{d x} = 1

= b^{2} \cdot 3 (0 - 1)

Simplify

= - 3 b^{2}

y^{^{''}} - 30 y^{^{'}} + 255 y = 0

\frac{d}{d x} ((2 x - x^{2})^{\frac{1}{2}})

\frac{\partial}{\partial x} (\frac{( x - y )}{( x + y )})

\frac{\partial}{\partial x} (e^{x + y + 3})

(\frac{x ^{3}}{3})^{^{'}}

What is the derivative of y=b^2(a-x)3 ?
The derivative of y=b^2(a-x)3 is -3b^2
What is the first derivative of y=b^2(a-x)3 ?
The first derivative of y=b^2(a-x)3 is -3b^2