What is the derivative of (8x+x^2/((4+x)^2)) ?

The derivative of (8x+x^2/((4+x)^2)) is (32)/((4+x)^3)

What is the first derivative of (8x+x^2/((4+x)^2)) ?

The first derivative of (8x+x^2/((4+x)^2)) is (32)/((4+x)^3)

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\frac{d}{d x} (\frac{8 x + x ^{2}}{( 4 + x ) ^{2}})

\frac{32}{( 4 + x ) ^{3}}

Solution steps

\frac{d}{d x} (\frac{8 x + x ^{2}}{( 4 + x ) ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 8 x + x ^{2} ) ( 4 + x ) ^{2} - \frac{d}{d x} ( ( 4 + x ) ^{2} ) ( 8 x + x ^{2} )}{( ( 4 + x ) ^{2} ) ^{2}}

\frac{d}{d x} (8 x + x^{2}) = 8 + 2 x

\frac{d}{d x} ((4 + x)^{2}) = 2 (4 + x)

= \frac{( 8 + 2 x ) ( 4 + x ) ^{2} - 2 ( 4 + x ) ( 8 x + x ^{2} )}{( ( 4 + x ) ^{2} ) ^{2}}

Simplify

\frac{( 8 + 2 x ) ( 4 + x ) ^{2} - 2 ( 4 + x ) ( 8 x + x ^{2} )}{( ( 4 + x ) ^{2} ) ^{2}} : \frac{32}{( 4 + x ) ^{3}}

= \frac{32}{( 4 + x ) ^{3}}

f (x) = 13 x^{3} (x^{2} - 3)

y = \frac{x}{81 + x ^{2}}, (0, 0)

\int \frac{14}{x ( x ^{2} + 25 )} d x

y^{^{''}} - 4 y^{^{'}} - 5 y = 0

x + y^{2} = 42, x = y

What is the derivative of (8x+x^2/((4+x)^2)) ?
The derivative of (8x+x^2/((4+x)^2)) is (32)/((4+x)^3)
What is the first derivative of (8x+x^2/((4+x)^2)) ?
The first derivative of (8x+x^2/((4+x)^2)) is (32)/((4+x)^3)