What is the derivative of ln(4x-2y+6) ?

The derivative of ln(4x-2y+6) is (-\frac{dy)/(dx)+2}{2x-y+3}

What is the first derivative of ln(4x-2y+6) ?

The first derivative of ln(4x-2y+6) is (-\frac{dy)/(dx)+2}{2x-y+3}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (ln (4 x - 2 y + 6))

\frac{- \frac{d y}{d x} + 2}{2 x - y + 3}

Solution steps

\frac{d}{d x} (ln (4 x - 2 y + 6))

Apply the chain rule:

\frac{1}{4 x - 2 y + 6} \frac{d}{d x} (4 x - 2 y + 6)

= \frac{1}{4 x - 2 y + 6} \frac{d}{d x} (4 x - 2 y + 6)

\frac{d}{d x} (4 x - 2 y + 6) = - 2 \frac{d y}{d x} + 4

= \frac{1}{4 x - 2 y + 6} (- 2 \frac{d y}{d x} + 4)

Simplify

\frac{1}{4 x - 2 y + 6} (- 2 \frac{d y}{d x} + 4) : \frac{- \frac{d y}{d x} + 2}{2 x - y + 3}

= \frac{- \frac{d y}{d x} + 2}{2 x - y + 3}

y^{^{''}} + 9 y = 3 sin (2 x)

x \to 4 - lim (2)

y^{^{''}} + 2 y^{^{'}} = 8

y^{^{'}} = - \frac{y}{2000} 4, y (0) = 70

\int_{0}^{\frac{π}{8}} x (sec (2 x))^{2} d x

What is the derivative of ln(4x-2y+6) ?
The derivative of ln(4x-2y+6) is (-\frac{dy)/(dx)+2}{2x-y+3}
What is the first derivative of ln(4x-2y+6) ?
The first derivative of ln(4x-2y+6) is (-\frac{dy)/(dx)+2}{2x-y+3}