What is (\partial)/(\partial x)(y(2-x-y)) ?

The answer to (\partial)/(\partial x)(y(2-x-y)) is -y

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(\partial)/(\partial x)(y(2-x-y))

\frac{\partial}{\partial x} (y (2 - x - y))

- y

Solution steps

\frac{\partial}{\partial x} (y (2 - x - y))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= y \frac{\partial}{\partial x} (2 - x - y)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= y (\frac{\partial}{\partial x} (2) - \frac{\partial}{\partial x} (x) - \frac{\partial}{\partial x} (y))

\frac{\partial}{\partial x} (2) = 0

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (y) = 0

= y (0 - 1 - 0)

Simplify

= - y

\frac{\partial}{\partial z} (5 z)

f (x) = 2 x^{3}, at x = - 2

\int \frac{1}{x 64 x ^{2} - 2} d x

\int \frac{1}{x ^{2} + 16} d x

What is (\partial)/(\partial x)(y(2-x-y)) ?
The answer to (\partial)/(\partial x)(y(2-x-y)) is -y