What is the tangent of f(x)=(x^2-1)^2,(-2,9) ?

The tangent of f(x)=(x^2-1)^2,(-2,9) is y=-24x-39

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tangent of f(x)=(x^2-1)^2,(-2,9)

tangent of

f (x) = (x^{2} - 1)^{2}, (- 2, 9)

y = - 24 x - 39

Solution steps

Find the slope of

f (x) = (x^{2} - 1)^{2} : \frac{df ( x )}{d x} = 4 x (x^{2} - 1)

Compute the slope of

f (x) = (x^{2} - 1)^{2}

(- 2, 9) : m = - 24

Find the line with slope m=

- 24

and passing through

(- 2, 9) : y = - 24 x - 39

y = - 24 x - 39

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What is the tangent of f(x)=(x^2-1)^2,(-2,9) ?
The tangent of f(x)=(x^2-1)^2,(-2,9) is y=-24x-39