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Popular >

2ty^'+4y=3

Solution

2 t y^{^{'}} + 4 y = 3

Solution

y = - \frac{c _{1}}{4 t ^{2}} + \frac{3}{4}

Solution steps

2 t y^{'} (t) + 4 y = 3

Solve separable ODE:

y = - \frac{c _{1}}{4 t ^{2}} + \frac{3}{4}

y = - \frac{c _{1}}{4 t ^{2}} + \frac{3}{4}

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Frequently Asked Questions (FAQ)

What is the solution for 2ty^'+4y=3 ?
The solution for 2ty^'+4y=3 is y=-(c_{1})/(4t^2)+3/4