What is the derivative of y= t/((t-8)^2) ?

The derivative of y= t/((t-8)^2) is (-8-t)/((t-8)^3)

What is the first derivative of y= t/((t-8)^2) ?

The first derivative of y= t/((t-8)^2) is (-8-t)/((t-8)^3)

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derivative of

y = \frac{t}{( t - 8 ) ^{2}}

\frac{- 8 - t}{( t - 8 ) ^{3}}

Solution steps

\frac{d}{d t} (\frac{t}{( t - 8 ) ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d t}{d t} ( t - 8 ) ^{2} - \frac{d}{d t} ( ( t - 8 ) ^{2} ) t}{( ( t - 8 ) ^{2} ) ^{2}}

\frac{d t}{d t} = 1

\frac{d}{d t} ((t - 8)^{2}) = 2 (t - 8)

= \frac{1 \cdot ( t - 8 ) ^{2} - 2 ( t - 8 ) t}{( ( t - 8 ) ^{2} ) ^{2}}

Simplify

\frac{1 \cdot ( t - 8 ) ^{2} - 2 ( t - 8 ) t}{( ( t - 8 ) ^{2} ) ^{2}} : \frac{- 8 - t}{( t - 8 ) ^{3}}

= \frac{- 8 - t}{( t - 8 ) ^{3}}

\int_{0}^{\frac{π}{2}} x sin (\frac{x}{3}) d x

\frac{\partial}{\partial s} (- 2 s^{2} + t^{2})

\frac{\partial}{\partial x} (x - 2 y)

\frac{d}{d x} (5 arcsin (x^{4}))

\int 23 e^{39 x} d x

What is the derivative of y= t/((t-8)^2) ?
The derivative of y= t/((t-8)^2) is (-8-t)/((t-8)^3)
What is the first derivative of y= t/((t-8)^2) ?
The first derivative of y= t/((t-8)^2) is (-8-t)/((t-8)^3)