What is the solution for xy^2(dy)/(dx)=y^3-x^3,y(1)=4 ?

The solution for xy^2(dy)/(dx)=y^3-x^3,y(1)=4 is y=x\sqrt[3]{-3ln(x)+64}

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xy^2(dy)/(dx)=y^3-x^3,y(1)=4

x y^{2} \frac{d y}{d x} = y^{3} - x^{3}, y (1) = 4

Solution steps

x y^{2} \frac{d y}{d x} = y^{3} - x^{3}

Solve Bernoulli ODE:

cos (3 x^{2})

\frac{d y}{d x} = - 9 y, y (0) = - 5

\frac{8 + 5 x}{x ^{2} + 9}

\int_{0}^{\frac{π}{2}} 9 cos^{5} (x) d x

\int e^{2 x} x + \frac{3}{2} e^{2 x} d x

What is the solution for xy^2(dy)/(dx)=y^3-x^3,y(1)=4 ?
The solution for xy^2(dy)/(dx)=y^3-x^3,y(1)=4 is y=x\sqrt[3]{-3ln(x)+64}