What is the integral from 0 to \sqrt[4]{x of}x^2+y^3 ?

The integral from 0 to \sqrt[4]{x of}x^2+y^3 is x^2\sqrt[4]{x}+x/4

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integral from 0 to \sqrt[4]{x of}x^2+y^3

Solution steps

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

x \to 6 lim (- x^{2} + 3 x - 6)

\frac{\partial}{\partial x} (2 x y - 3 y cos (x) + 5 y^{2})

\int \frac{3 x + ( 2 )}{( x )} d x

\int ((6 x + 5)^{2}) d x

What is the integral from 0 to \sqrt[4]{x of}x^2+y^3 ?
The integral from 0 to \sqrt[4]{x of}x^2+y^3 is x^2\sqrt[4]{x}+x/4