What is the derivative of ln(3x^2-2x+1) ?

The derivative of ln(3x^2-2x+1) is (6x-2)/(3x^2-2x+1)

What is the first derivative of ln(3x^2-2x+1) ?

The first derivative of ln(3x^2-2x+1) is (6x-2)/(3x^2-2x+1)

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\frac{d}{d x} (ln (3 x^{2} - 2 x + 1))

\frac{6 x - 2}{3 x ^{2} - 2 x + 1}

Solution steps

\frac{d}{d x} (ln (3 x^{2} - 2 x + 1))

Apply the chain rule:

\frac{1}{3 x ^{2} - 2 x + 1} \frac{d}{d x} (3 x^{2} - 2 x + 1)

= \frac{1}{3 x ^{2} - 2 x + 1} \frac{d}{d x} (3 x^{2} - 2 x + 1)

\frac{d}{d x} (3 x^{2} - 2 x + 1) = 6 x - 2

= \frac{1}{3 x ^{2} - 2 x + 1} (6 x - 2)

Simplify

\frac{1}{3 x ^{2} - 2 x + 1} (6 x - 2) : \frac{6 x - 2}{3 x ^{2} - 2 x + 1}

= \frac{6 x - 2}{3 x ^{2} - 2 x + 1}

\int_{0}^{π} cos^{3} (x) d x

ln (r)

\int_{0}^{3} (x^{3} - 5 x) d x

sin (x^{3})

x y^{^{''}} = y^{^{'}} + x (y^{^{'}})^{2}

What is the derivative of ln(3x^2-2x+1) ?
The derivative of ln(3x^2-2x+1) is (6x-2)/(3x^2-2x+1)
What is the first derivative of ln(3x^2-2x+1) ?
The first derivative of ln(3x^2-2x+1) is (6x-2)/(3x^2-2x+1)