What is the limit as x approaches+0+of x^{x^8} ?

The limit as x approaches+0+of x^{x^8} is 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches+0+of x^{x^8}

x \to + 0 + lim (x^{x^{8}})

1

Solution steps

x \to 0 + lim (x^{x^{8}})

Apply exponent rules

= x \to 0 + lim (e^{x^{8} l n (x)})

Apply the Limit Chain Rule:

1

= 1

5 x y^{^{'}} - 2 y = - \frac{x ^{2}}{y ^{4}}

\int \frac{7}{4 - x ^{2}} d x

\frac{1}{( s - 1 ) ( s - 2 ) ( s - 3 )}

x \to 3 - lim (x 9 - x^{2})

\int tan (x) - sin (x) sin (y) d x

What is the limit as x approaches+0+of x^{x^8} ?
The limit as x approaches+0+of x^{x^8} is 1