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Popular >

xy^'+y=y^2,y(1)=-5

Solution

x y^{^{'}} + y = y^{2}, y (1) = - 5

Solution

y = \frac{5}{- 6 x + 5}

Solution steps

x y^{'} (x) + y = y^{2}

Solve Bernoulli ODE:

y = \frac{5}{- 6 x + 5}

y = \frac{5}{- 6 x + 5}

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x \to - 5 lim (4 x^{2} - 8)

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Frequently Asked Questions (FAQ)

What is the solution for xy^'+y=y^2,y(1)=-5 ?
The solution for xy^'+y=y^2,y(1)=-5 is y= 5/(-6x+5)