What is the limit as t approaches 3 of (t^2)/(9-t^2) ?

The limit as t approaches 3 of (t^2)/(9-t^2) is diverges

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limit as t approaches 3 of (t^2)/(9-t^2)

t \to 3 lim (\frac{t ^{2}}{9 - t ^{2}})

diverges

Solution steps

t \to 3 lim (\frac{t ^{2}}{9 - t ^{2}})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

t \to 3 + lim (\frac{t ^{2}}{9 - t ^{2}}) = - \infty

t \to 3 - lim (\frac{t ^{2}}{9 - t ^{2}}) = \infty

= diverges

x^{3}, 4

\frac{d}{d t} (\frac{sin ( t )}{t})

\int \frac{x - 1}{3 x ^{2} - 4 x + 3} d x

\int \frac{x + 3}{x ^{2} - 3 x + 2} d x

n = 5 \sum \infty e^{\frac{1}{n}}

What is the limit as t approaches 3 of (t^2)/(9-t^2) ?
The limit as t approaches 3 of (t^2)/(9-t^2) is diverges