What is the derivative of y=(\sqrt[3]{x})/8 ?

The derivative of y=(\sqrt[3]{x})/8 is 1/(24x^{2/3)}

What is the first derivative of y=(\sqrt[3]{x})/8 ?

The first derivative of y=(\sqrt[3]{x})/8 is 1/(24x^{2/3)}

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derivative of

\frac{1}{24 x ^{\frac{2}{3}}}

Solution steps

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

Apply radical rule:

= \frac{1}{8} \frac{d}{d x} (x^{\frac{1}{3}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{8} \cdot \frac{1}{3} x^{\frac{1}{3} - 1}

Simplify

\frac{1}{8} \cdot \frac{1}{3} x^{\frac{1}{3} - 1} : \frac{1}{24 x ^{\frac{2}{3}}}

= \frac{1}{24 x ^{\frac{2}{3}}}

x \to 0 lim (tanh (x))

\frac{1}{2} (e^{x} - e^{- x})

\int \frac{x ^{n}}{n + 1} d x

(78) (7 - 9)

e^{- t \cdot 3}

What is the derivative of y=(\sqrt[3]{x})/8 ?
The derivative of y=(\sqrt[3]{x})/8 is 1/(24x^{2/3)}
What is the first derivative of y=(\sqrt[3]{x})/8 ?
The first derivative of y=(\sqrt[3]{x})/8 is 1/(24x^{2/3)}