What is the derivative of 3\sqrt[4]{x} ?

The derivative of 3\sqrt[4]{x} is 3/(4x^{3/4)}

What is the first derivative of 3\sqrt[4]{x} ?

The first derivative of 3\sqrt[4]{x} is 3/(4x^{3/4)}

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\frac{3}{4 x ^{\frac{3}{4}}}

Solution steps

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

Apply radical rule:

= 3 \frac{d}{d x} (x^{\frac{1}{4}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 3 \cdot \frac{1}{4} x^{\frac{1}{4} - 1}

Simplify

3 \cdot \frac{1}{4} x^{\frac{1}{4} - 1} : \frac{3}{4 x ^{\frac{3}{4}}}

= \frac{3}{4 x ^{\frac{3}{4}}}

\int \frac{( x ^{2} + 1 )}{x ^{2} ( x + 1 ) ^{3}} d x

\int tan (11 x se) c^{2} 11 x d x

\frac{d P}{d t} = P (1 - P)

\frac{d}{d x} (\frac{ln ( 2 x - 1 )}{x ^{2} - 1})

x \to 0 lim (x^{2} + 5 x + 6)

What is the derivative of 3\sqrt[4]{x} ?
The derivative of 3\sqrt[4]{x} is 3/(4x^{3/4)}
What is the first derivative of 3\sqrt[4]{x} ?
The first derivative of 3\sqrt[4]{x} is 3/(4x^{3/4)}