What is the integral of 0.0015x^2 ?

The integral of 0.0015x^2 is 0.0005x^3+C

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integral of 0.0015x^2

\int 0.0015 x^{2} d x

0.0005 x^{3} + C

Solution steps

\int 0.0015 x^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 0.0015 \cdot \int x^{2} d x

Apply the Power Rule

: \frac{x ^{3}}{3}

= 0.0015 \cdot \frac{x ^{3}}{3}

Simplify

0.0015 \cdot \frac{x ^{3}}{3} : 0.0005 x^{3}

= 0.0005 x^{3}

Add a constant to the solution

= 0.0005 x^{3} + C

\frac{\partial}{\partial x} (\frac{y x}{y + x})

x \to 2 lim (x^{2} + 3 x + 1)

x \to 0 lim (\frac{ln ( sin ( 2 x ) )}{ln ( tan ( x ) )})

\int \frac{1}{9 - 81 x ^{2}} d x

\frac{d}{d x} (\frac{2 x}{3 - cot ( x )})