What is the tangent of f(x)=-x^2-2x-2,\at x=-3 ?

The tangent of f(x)=-x^2-2x-2,\at x=-3 is y=4x+7

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tangent of f(x)=-x^2-2x-2,\at x=-3

tangent of

f (x) = - x^{2} - 2 x - 2, at x = - 3

y = 4 x + 7

Solution steps

Find the tangent point:

(- 3, - 5)

Find the slope of

f (x) = - x^{2} - 2 x - 2 : \frac{df ( x )}{d x} = - 2 x - 2

Compute the slope of

f (x) = - x^{2} - 2 x - 2

x = - 3 : m = 4

Find the line with slope m=

4

and passing through

(- 3, - 5) : y = 4 x + 7

y = 4 x + 7

\int \frac{I n ( x )}{x ^{2}} d x

\int \frac{x ^{3}}{x ^{2} + 5} d x

\int (2 x + 4) d x

\frac{d}{d x} (tan (\frac{π}{3}))

\int - \frac{6 x ^{3} + 8 x}{x ^{4} - 16} d x

What is the tangent of f(x)=-x^2-2x-2,\at x=-3 ?
The tangent of f(x)=-x^2-2x-2,\at x=-3 is y=4x+7