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Popular >

integral from 0 to 5 of |x-2|

Solution

\int_{0}^{5} ∣ x - 2 ∣ d x

Solution

\frac{13}{2}

+1

Decimal Notation

6.5

Solution steps

\int_{0}^{5} ∣ x - 2 ∣ d x

Eliminate Absolutes

= \int_{0}^{2} - x + 2 d x + \int_{2}^{5} x - 2 d x

\int_{0}^{2} - x + 2 d x = 2

\int_{2}^{5} x - 2 d x = \frac{9}{2}

= 2 + \frac{9}{2}

Simplify

2 + \frac{9}{2} : \frac{13}{2}

= \frac{13}{2}

Popular Examples

taylor (1+x)^5 taylor

(1 + x)^{5}

integral from 0 to 9 of 1/((x-1)^{1/3)}

\int_{0}^{9} \frac{1}{( x - 1 ) ^{\frac{1}{3}}} d x

tangent of f(x)=x^3-2x^2-5x+6,\at x=2 tangent of

f (x) = x^{3} - 2 x^{2} - 5 x + 6, at x = 2

integral from 0 to 3 of 15sqrt(8x+1)

\int_{0}^{3} 15 8 x + 1 d x

integral of ge^{-ct}

\int g e^{- c t} d t

Frequently Asked Questions (FAQ)

What is the integral from 0 to 5 of |x-2| ?
The integral from 0 to 5 of |x-2| is 13/2