What is the limit as x approaches 8 of 3/((x-8)^2) ?

The limit as x approaches 8 of 3/((x-8)^2) is infinity

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limit as x approaches 8 of 3/((x-8)^2)

x \to 8 lim (\frac{3}{( x - 8 ) ^{2}})

\infty

Solution steps

x \to 8 lim (\frac{3}{( x - 8 ) ^{2}})

x \to a - lim f (x) = x \to a + lim f (x) = L

then

x \to a lim f (x) = L

x \to 8 - lim (\frac{3}{( x - 8 ) ^{2}}) = \infty

x \to 8 + lim (\frac{3}{( x - 8 ) ^{2}}) = \infty

= \infty

\int 13 tan^{4} (x) sec^{6} (x) d x

\frac{6 x}{x + 5}

f (x) = 2 x^{2} - 6 x + 4

\int e^{(- s + 4) t} t d t

x \to 1 lim (\frac{x ^{- 2} - 6 ^{- 2}}{x + 6})

What is the limit as x approaches 8 of 3/((x-8)^2) ?
The limit as x approaches 8 of 3/((x-8)^2) is infinity