What is inverse oflaplace 4t ?

The answer to inverse oflaplace 4t is 4\delta'(t)

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inverse oflaplace 4t

inverse laplace

4 t

4 δ' (t)

Solution steps

L^{- 1} {4 t}

Use the constant multiplication property of Inverse Laplace Transform:

For function

f (t)

and constant

a : L^{- 1} {a \cdot f (t)} = a \cdot L^{- 1} {f (t)}

= 4 L^{- 1} {t}

L^{- 1} {t} : δ^{'} (t)

= 4 δ^{^{'}} (t)

x \to 14 - lim (ln (14 - x))

y = e^{9 x} cos (π x), (0, 1)

ln (2 - x)

3 x^{3}

y^{^{'}} = x ln (x)

What is inverse oflaplace 4t ?
The answer to inverse oflaplace 4t is 4\delta'(t)