What is the integral of 1/(1+21x) ?

The integral of 1/(1+21x) is 1/21 ln|1+21x|+C

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integral of 1/(1+21x)

\int \frac{1}{1 + 21 x} d x

\frac{1}{21} ln ∣ 1 + 21 x ∣ + C

Solution steps

\int \frac{1}{1 + 21 x} d x

Apply u-substitution

: \int \frac{1}{21 u} d u

= \int \frac{1}{21 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{21} \cdot \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= \frac{1}{21} ln ∣ u ∣

Substitute back

u = 1 + 21 x

= \frac{1}{21} ln ∣ 1 + 21 x ∣

Add a constant to the solution

= \frac{1}{21} ln ∣ 1 + 21 x ∣ + C

f (x) = e^{8}

\int cos (x) - sin (x) d x

y = 1 - x^{4}, y = 0

\frac{\partial}{\partial y} ((x e^{y})^{2})

f (x) = \frac{x ^{2}}{2}

What is the integral of 1/(1+21x) ?
The integral of 1/(1+21x) is 1/21 ln|1+21x|+C