What is the derivative of 2x^4+7x+5 ?

The derivative of 2x^4+7x+5 is 8x^3+7

What is the first derivative of 2x^4+7x+5 ?

The first derivative of 2x^4+7x+5 is 8x^3+7

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\frac{d}{d x} (2 x^{4} + 7 x + 5)

8 x^{3} + 7

Solution steps

\frac{d}{d x} (2 x^{4} + 7 x + 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{4}) + \frac{d}{d x} (7 x) + \frac{d}{d x} (5)

\frac{d}{d x} (2 x^{4}) = 8 x^{3}

\frac{d}{d x} (7 x) = 7

\frac{d}{d x} (5) = 0

= 8 x^{3} + 7 + 0

Simplify

= 8 x^{3} + 7

x \to - \infty lim (\frac{7}{x})

\int x (x + 2) d x

(ln (5 x))^{2}

\frac{d}{d x} (lo g_{2} (x))

(e^{- t} sin (t))^{^{'}}

What is the derivative of 2x^4+7x+5 ?
The derivative of 2x^4+7x+5 is 8x^3+7
What is the first derivative of 2x^4+7x+5 ?
The first derivative of 2x^4+7x+5 is 8x^3+7