What is (\partial)/(\partial y)(2(x+y)) ?

The answer to (\partial)/(\partial y)(2(x+y)) is 2

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(\partial)/(\partial y)(2(x+y))

\frac{\partial}{\partial y} (2 (x + y))

2

Solution steps

\frac{\partial}{\partial y} (2 (x + y))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{\partial}{\partial y} (x + y)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= 2 (\frac{\partial}{\partial y} (x) + \frac{\partial}{\partial y} (y))

\frac{\partial}{\partial y} (x) = 0

\frac{\partial}{\partial y} (y) = 1

= 2 (0 + 1)

Simplify

= 2

\frac{\partial}{\partial x} (\frac{2 x - y}{x + 3 y})

x \to 2 - lim (x + c)

\int x - \frac{2}{x} d x

\int sec^{2} (θ) tan (θ) d θ

\int e^{- (x^{3})^{3}} d (x^{3})^{3}

What is (\partial)/(\partial y)(2(x+y)) ?
The answer to (\partial)/(\partial y)(2(x+y)) is 2