What is the limit as x approaches 0+of x^{9x} ?

The limit as x approaches 0+of x^{9x} is 1

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limit as x approaches 0+of x^{9x}

x \to 0 + lim (x^{9 x})

1

Solution steps

x \to 0 + lim (x^{9 x})

Apply exponent rules

= x \to 0 + lim (e^{9 x l n (x)})

Apply the Limit Chain Rule:

1

= 1

\frac{\partial}{\partial x} (5 x^{2})

\int \frac{x}{6 - x ^{2}} d x

x \to 3 lim (x^{2})

\int e^{x} y d x

x \to - 1 lim (\frac{x ^{2} - 4}{x - 2})

What is the limit as x approaches 0+of x^{9x} ?
The limit as x approaches 0+of x^{9x} is 1